User talk:Mitchc/mathsCassigmentwork

Im just going to start typing my maths assigment here because it will make it a lot easier with all the math symbols. Ill delete this page later. ^_^	+	$$ \sum_{i=1}^{N-1}$$ -	 	+	$$\sum_{i=1}^{n-1} \letf (\frac {top}{bottom} \right)$$ -	$$ \pi\ \int_{x_0}^{x_n} \, y^2 dx $$	+ -	 	+	-	 	+	-	$$ \pi\ \int_{y_0}^{y_n} \, x^2 dy $$	+ -	 	+	-	$$ x^2 + y^2 = a^2 $$	+ -	 	+	-	$$ x^2 + y^2 = 25 $$	+ -	 	+	-	$$ x^2 + 1^2 = 25 $$	+ -	 	+	-	$$ x^2 = 25 - 1 $$	+ -	 	+	-	$$ x^2 = 24 $$	+ -	 	+	-	$$ x = \pm \;\sqrt{24}$$	+ -	 	+	-	 	+	-	$$ \pi\ \int_{-\sqrt{24}}^{\sqrt{24}} \, 25 - x^2 dx $$	+ -	 	+	-	$$\pi\ \Bigg\lfloor 25x - \frac {x^3}{3} + C \Bigg\rceil_{-\sqrt{24}}^{\sqrt{24}} $$	+ -	 	+	-	$$\pi\ \Bigg\lfloor \left ( 25\sqrt{24} - \frac {\sqrt{24}^3}{3} + C \right )\, - \, \left ( -25\sqrt{24} - \frac {(-\sqrt{24})^3}{3} + C \right ) \Bigg\rceil $$	+ -	 	+	-	$$ \pi\,r^2h $$	+ -	 	+	-	$$ \pi\,1^2 \, 2\sqrt{24}$$	+ -	 	+	-	$$ \frac {x^2}{a^2} + \frac {y^2}{b^2} = 1 $$	+ -	 	+	-	 	+	-	$$ \frac {x^2}{64} + \frac {y^2}{16} = 1 $$	+ -	 	+	-	$$ \frac {x^2}{64} + \frac {1^2}{16} = 1 $$	+ -	 	+	-	$$ \frac {x^2}{64} = 1 - \frac {1}{16} $$	+ -	 	+	-	$$ x^2 = \left ( \frac{15}{16} \right )64 $$	+ -	 	+	-	$$ x^2 = 60 $$	+ -	 	+	-	$$ x = \pm \;\sqrt{60}$$	+ -	 	+	-	$$ y^2 = \frac {63}{4}$$	+ -	 	+	-	$$ \frac {y^2}{16} = 1 - \frac {x^2}{64} $$	+ -	 	+	-	$$ y^2 = \left ( 1 - \frac {x^2}{64} \right )16 $$	+ -	 	+	-	$$ y^2 = 16 - \frac {x^2}{4} $$	+ -	 	+	-	$$ \pi\ \int_{- \sqrt{60}}^{\sqrt{60}} \, 16 - \frac {x^2}{4} \,dx $$	+ -	 	+	-	$$\pi\ \Bigg\lfloor 16x - \frac {x^3}{12} + C \Bigg\rceil_{-\sqrt{60}}^{\sqrt{60}} $$	+ -	 	+	-	 	+	-	$$\pi\ \Bigg\lfloor \left ( 16\sqrt{60} - \frac {\sqrt{60}^3}{12} + C \right )\, - \, \left ( -16\sqrt{60} - \frac {(-\sqrt{60})^3}{12} + C \right ) \Bigg\rceil $$

$$ax^n + bx^{(n-1)}+ ...+ cx^{(n-n)} $$ $$3x^5 + x^3 + 2x^2 + 5$$

$$\frac {x^2 + 6x + 9}{x + 3}$$$$\frac {(x + 3)(x + 3)}{x + 3}$$

$$\frac {x^2 + 3x + 9}{x + 3}$$