Talk:Special Relativity/Relativistic dynamics

Oops
>Since the Hamiltonian is invariant with time, it represents the energy.

Not true in general. It's the energy in this case, but the quoted sentence doesn't provide justification for that. Work out $$T(v)=\tfrac 1 2 v^2 + \tfrac 1 6 v^3$$ sometime to see a counterexample where the Hamiltonian function isn't the same as the energy. --Eh9 (talk) 02:54, 11 August 2008 (UTC)