Talk:Circuit Theory/Power supplies

The analysis for the example 1, power dissipated in a resistor is wrong.

P=I^2*R, for ac over an integer number of wavelength, this is: P=(I_RMS)^2*R = (4/3)^2 / 2 * 20 = 17.8W

The integral method should not have the initial \tau as the first term, it should be: P = R/t int_(tau=0)(2pi/3){i^2 d(tau)}, not R/t int_(tau=0)(2pi/3){tau * i^2 d(tau)}

This gives 17.8W as found by the conventional P=(I_RMS)^2 * R