Talk:Calculus/Newton's Method

This is my first shot at this section, all feedback, edits, criticisms, and witicisms welcome. -- Etscrivner 8:27, 27 November 2005 (UTC)

Alternate Formula
I removed the following formula for $$x_{x+1}$$:
 * $$x_{n+1}=x_0-\sum_{i=0}^n\frac{f(x_i)}{f^\prime(x_i)}$$

This form still requires a knowledge of all previous $$x_i$$'s, and it requires many more operations than the formula
 * $$x_{n+1}=x_n-\frac{f(x_n)}{f^\prime(x_n)}$$

, so it seems to me to have no usefulness. Please feel free to restore it if you disagree, but I'd be curious to know your reasoning. --Greenbreen (discuss • contribs) 23:37, 15 July 2011 (UTC)