Circuit Theory/Phasors/proof1


 * $$g(t)=G_m cos(\omega t)$$ starting point
 * $$g(t)=G_m \operatorname{Re}(e^{j\omega t})$$
 * $$g(t)=G_m \operatorname{Re}(e^{j*0}e^{j\omega t})$$
 * $$g(t)=\operatorname{Re}(G_m e^{j0}e^{j\omega t})$$
 * $$g(t)=\operatorname{Re}(\mathbb{G} e^{j\omega t})$$
 * $$\mathbb{G} = G_m e^{j0} = G_m(cos(0) + j*sin(0)) = Gm$$