Chess/Puzzles/Placement/14 Bishops/Solution

There are several solutions to this puzzle, but they are all quite similar.

Here's a possible one:

Proof of maximality
There are 15 diagonals on the chessboard running from bottom left to top right. They are:
 * a8-a8
 * a7-b8
 * a6-c8
 * a5-d8
 * a4-e8
 * a3-f8
 * a2-g8
 * a1-h8
 * b1-h7
 * c1-h6
 * d1-h5
 * e1-h4
 * f1-h3
 * g1-h2
 * h1-h1

Each of these diagonals can only contain one bishop. Also, the first and last diagonals cannot both contain a bishop, since both are on the diagonal a8-h1. Therefore, we can place at most 13 bishops on the other 13 diagonals, and one bishop on those two diagonals, for a total of 14 bishops. Since 14 bishops is possible, 14 is the maximum number of bishops we can place so no two attack each other.